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Alchen [17]
3 years ago
10

Need help with this

Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer:

The first answer.

Step-by-step explanation:

First of all, the circle on -3 did not have filling so that means it is not equal to z. Then we look on the circle on 6. It does have a filling which means it is equal to and greater than z. Now we look in between -3 and 6. Is there any white spots? If no, then we don’t have to use an OR. Therefore, the first answer is the only plausible answer.

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If (72)p = 76, what is the value of p?<br><br> 2<br> 3<br> 4<br> 8
o-na [289]

Answer:

it would be +2

Step-by-step explanation:

the equation would be (72)+2= 76

3 0
4 years ago
What is the distance between the points (−4, 5) and (3, 5)?
puteri [66]

Answer:

idk but you should try getting photo math it's a

app that helps you with math

8 0
3 years ago
Read 2 more answers
Area of Composed figures<br><br> PLEASEEE RN
madam [21]

Answer:

33 ft²

Step-by-step explanation:

The area of the outdoor carpet = area of trapezoid + area of rectangle + area of triangle

✔️Area of trapezoid = ½(a + b)h

Where,

a = 6 ft

b = 3 ft

h = 11 - 9 = 2 ft

Area of trapezoid = ½(6 + 3)*2 = 9 ft²

✔️Area of rectangle = L*W = 7 *3 = 21 ft²

✔️Area of triangle = ½bh

b = 2 ft

h = 3 ft

Area = ½*2*3 = 3 ft²

✅Area of the outdoor carpet = 9 + 21 + 3 = 33 ft²

5 0
3 years ago
(8.9x108)
KatRina [158]

Answer:

the correct answer is 3x104

8 0
3 years ago
Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial t
jekas [21]

Answer:

(12.1409, 14.0591

Step-by-step explanation:

Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.

Group   Group One     Group Two  

Mean 87.600 74.500

SD 1.000 1.500

SEM 0.316 0.433

N 10      12    

The mean of Group One minus Group Two equals 13.100

standard error of difference = 0.556

 90% confidence interval of this difference:  

(13.1-1.725*0.556,13.1+1.725*0.556)\\=(12.1409, 14.0591)

  t = 23.5520

 df = 20

4 0
3 years ago
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