So x=x
and y=pounds
when x=0, y=64
when x=1, y=63.1
to find slope, (y1-y2)/(x1-x2)=(64-63.1)/(0-1)=0.9/-1=-0.9=slope
y=-0.9x+b
subsitute
64=-0.9(0)+b
b=64
y=-0.9+64
so int 2001, x=11
y=-0.9(11)+64
y=-9.9+64
y=54.1
Answer:
-1/20
Step-by-step explanation:
For a graph like this you should make the gallons of gas on y-axis and the miles driven on the x-axis.
To find slope the formula is (y2-y1)/(x2-x1)
So in this case it is 2-4/40-0
-2/40
This reduces to -1/20
The first term of an AP can be defined as T1 i.e. n=1. According to the given equation,. T1=a=2(1)+9=11.
Answer:
x = - 4, 0, 3, 4
Step-by-step explanation:
Given
f(x) = - 5x(x² - 16)(x - 3) ← x² - 16 is a difference of squares, thus
f(x) = - 5x(x - 4)(x + 4)(x - 3)
To find the zeros, equate f(x) to zero, that is
- 5x(x - 4)(x + 4)(x - 3) = 0
Equate each factor to zero and solve for x
- 5x = 0 ⇒ x = 0
x - 4 = 0 ⇒ x = 4
x + 4 = 0 ⇒ x = - 4
x - 3 = 0 ⇒ x = 3
Thus the zeros are
x = - 4, x = 0, x = 3, x = 4
The appropriate choice is ...
B. 1/7, 3/4, 5, 7
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Only the magnitude of the vertical scale factor affects the apparent width of the graph. The higher its value, the narrower the graph appears to be.
