Find the surface area of a cube that is 5/8
2 answers:
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Answer:
Solution (1.8,1.61)
Step-by-step explanation:
Let us do it one by one.
Graph 1 :
y=-3x+7
Let us find some random coordinates to graph this equation
x = 0 ; y = -3(0)+7 = 7
(0,7)
x=1 ; y=-3(1) + 7 = -3+7=4
(1,4)
Plotting these coordinates on graph , and joining them will give us the line on the graph.
Graph 2 :
y = Sqrt ( 2x-1)
let us find random cordinates for some values of x
x=1, y = sqrt (2(1)-1) = sqrt (1) = 1
(1,1)
x=0.5 , y = sqrt (2(0.5)-1) = sqrt (0) = 0
(0.5,0)
Hence we have two coordinates , now we also see that , after comparing it from standard form of an square root function,
the square root function is upper half of parabola opening towards right and the point of origin is (0.5,0)
Let us find the solution , for that we need to put y=-3x+7 in y=sqrt (2x-1)
and we get
-3x+7=sqrt (2x-1)
squaring on both sides we get
9x^2+49-42x=2x-1
9x^2-44x+50=0
solving it with quadratic formula
x=[-b+sqrt(b^2-4ac)]/2a
we get x = 1.8 and replacing it in first equation we get y = 1.61
Hence the solution will be (1.8,1.61)
