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RUDIKE [14]
2 years ago
10

Ahab jumped 2 times in 4 minutes. at that rate, how many times would he jump in 9 hours?

Mathematics
1 answer:
jeka57 [31]2 years ago
7 0

Answer: 270

Step-by-step explanation: 20 mins = 10 jumps now 20x3 is 60 which is an hour so in an hour he would have jumped 30 times and if you times 30 with 9 you would get 270 hence your answer

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a waiter earns $128 for 6 hours of work.The total included $86 in tips.How much does the waiter earn each hour
marta [7]
To find this out, subtract the tip from the total:

$128 - $86= $42

Then divide the 42 by 6:

42 / 6 = 7

So the waiter earns $7 per hour.

Hope this helps!
6 0
3 years ago
An obtuse triangle has a side length of $16,$ and a side length of $21.$ The third side length is also a positive integer. How m
Ymorist [56]

Answer:

3

Step-by-step explanation:

3 0
3 years ago
Convert 800 milliliters to liters.<br><br> A. 8 L<br> B. 80 L<br> C. 0.8 L<br> D. 0.08 L
ANTONII [103]
The answer is c. 0.8 L
7 0
3 years ago
Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
Find the inverse of each relation<br><br> (-3,-7) (0,-1) (5,9) (7,13)
masha68 [24]
(-7,-3) (-1,0) (9,5) and (13,7)
8 0
3 years ago
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