1) We have that the equation is
![x^2=20y](https://tex.z-dn.net/?f=x%5E2%3D20y)
, hence y=x^2/20. The standard equation of such an equation is y=
![\frac{1}{4p} x^2](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4p%7D%20x%5E2)
. Hence, p=5 in this case. The focus is at (0,5) and the directrix is at y=-5 (a tip is that the directrix is always "opposite" the focus point of a parabola; if the directrix is at x=-7 for example, the focus is at (7,0)).
2) Similarly, we have that the equation is
![x=3y^2 \\ \frac{1}{4p} =3](https://tex.z-dn.net/?f=x%3D3y%5E2%20%5C%5C%20%20%5Cfrac%7B1%7D%7B4p%7D%20%3D3)
. Thus, p=1/12. In this case, the parabola opens along the x-axis and the focus is at (1/12, 0). Also, the directrix is at x=-1/12. Hence the correct answer is B.
3) We are given that the parabola has a p of 9. Also, the focus lies along the y-axis, hence the parabola is opening along the y-axis. Finally, the focus is on the positive half, so the parabola is opening upwards. The equation for this case is y=
![y=\frac{1}{4p} x^2= \frac{1}{36 } x^2](https://tex.z-dn.net/?f=%20y%3D%5Cfrac%7B1%7D%7B4p%7D%20x%5E2%3D%20%5Cfrac%7B1%7D%7B36%20%7D%20x%5E2)
.
4) Similarly as above. The directrix is superfluous, we only need the p-value. THe same comments about the parabola apply and if we substitute p=8 in the formula:
![y= \frac{1}{4p} x^2](https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B1%7D%7B4p%7D%20x%5E2%20)
we get y=
![\frac{1}{32} x^2](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B32%7D%20x%5E2)
.
5) This is somewhat different, even though we do not need the directrix again. The focus lies on the x-axis, thus the parabola opens in this direction. The focus lies on the positive part of the axis, thus the parabola opens to the right. We also are given p=7. Hence, the equation we need is of the form
![x= \frac{1}{4p} y^2](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B1%7D%7B4p%7D%20y%5E2)
. Substituting p=7, we get
![x= \frac{1}{28} y^2](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B1%7D%7B28%7D%20y%5E2)
.
6) The equation of a prabola with a vertex at (0,0) is of the form y=-ax^2. The minus sign is needed since the parabola is downwards. Since we are given anothe point, we can calculate a. We have to take y=-74 and x=14 feet (since left to right is 28, we need to take half).
![-a= \frac{y}{x^2} = \frac{-74}{14^2} =-0.378](https://tex.z-dn.net/?f=-a%3D%20%5Cfrac%7By%7D%7Bx%5E2%7D%20%3D%20%5Cfrac%7B-74%7D%7B14%5E2%7D%20%3D-0.378)
. Thus a=0.378. Hence the correct expressions is y=-0.378*