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Kamila [148]
2 years ago
11

Please help me with this

Mathematics
2 answers:
natta225 [31]2 years ago
4 0
The answer is the first one because rise over run which basically means how much it goes up divided by how much it goes over which equals 1.25 you’re welcome
kow [346]2 years ago
3 0

Answer:

The first one

Step-by-step explanation:

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Zanzabum
3x$2.49+2x$3.19+4x$4.99=$33.81
4 0
3 years ago
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What are the zeros of x^2-5x-1
nexus9112 [7]
The zeros is another name for solutions.

x^2 - 5x - 1 = 0

You must use the quadratic formula to find x.

In the formula, a = 1, b = -5 and c = -1.

Plug into formula and solve for x.

The values of x are the zeros of the function.
3 0
3 years ago
Expand (p+q)² = p² + 2pq+q²​
castortr0y [4]

Answer:

The answer already exists in your question...

That is correct expansion

7 0
2 years ago
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First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
A video game has the following formula: For every 1,333 in attack power, you gain 3 levels. You get one bonus star per every 38
aleksley [76]

Answer:

Rounded to a whole number, the player has 12 bonus stars.

Step-by-step explanation:

Since the video game establishes that for every 1,333 points of attack power 3 levels are gained, and that the player has a total of 0.21 million attack points, to determine the number of levels that player has it is necessary to perform the following calculation :

0.21 million = 210,000

210,000 / 1,333 x 3 = Levels

472.6 = Levels

Now, every 38 levels, the game awards a bonus star. To determine the amount of bonus stars that the player has, the following division must be made:

472.6 / 38 = X

12.43 = X

Thus, rounded to a whole number, the player has 12 bonus stars.

7 0
3 years ago
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