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Dvinal [7]
3 years ago
13

Helppppppppppppppppppppppppppp

Mathematics
2 answers:
algol [13]3 years ago
8 0

Answer:

its B

Step-by-step explanation:

the heart was at -5,-7 so up 10× would be -5,5 and reflected vertically which is the y axis

Misha Larkins [42]3 years ago
3 0
The answer is b. Count up from heart 1. 10 units and then translate over the y axis which is always left or right. (X axis is up or down)
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Please find the surface area of each figure to the nearest tenth? Please show the work too...
MrRa [10]
The first one is 31.875 and the second is 12 I don't know how to explain to get it. Sorry
7 0
3 years ago
The following data comparing wait times at two rides at Disney are listed below: Position Pirates Splash Mountain Sample Size 32
myrzilka [38]

Answer:

a) (14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968

(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788

b) t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10  

Step-by-step explanation:

Data given and notation

\bar X_{A}=14.68 represent the mean for Pirates

\bar X_{B}=18.77 represent the mean for Splash Mountain

s_{A}=11.87 represent the sample standard deviation for the sample Pirates

s_{B}=16.79 represent the sample standard deviation for the sample Slpash Mountain

n_{A}=32 sample size selected for Pirates

n_{B}=30 sample size selected for Splash Mountain

\alpha=0.02 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

Part a

The confidence interval would be given by:

(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}

The degrees of freedom are given by:

df = n_A +n_B -2 = 32+30-2 = 60

Since we want 98% of confidence the significance level is \alpha =1-0.98 =0.02 and \alpha/2 =0.01, we can find in the t distribution with df =60 a critical value that accumulates 0.01 of the area on each tail and we got:

t_{\alpha/2}= 2.39

And replacing we got for the confidence interval:

(14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968

(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788

Part b

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the means are equal, the system of hypothesis would be:

Null hypothesis:\mu_{A} = \mu_{B}

Alternative hypothesis:\mu_{A} \neq \mu_{B}

the statistic is given by:

t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10  

6 0
2 years ago
Im giving 30 points pls help
gayaneshka [121]

Step-by-step explanation:

Pathagory and Theorem

a^2+b^2=c^2

(x-3)^2+(x-4)^2=6^2

expand:

2x^2-14x+25=36

2x^2-14x-11=0

x=(\sqrt{71}+7)/2

perimeter=(x-3)+(x-4)+6=2x-1

insert the value for x into 2x-1

\sqrt{71}+6=perimeter

Hope that helps :)

7 0
3 years ago
Read 2 more answers
Plz help me and answer right
azamat
I think it might be 30 but I don’t know
3 0
2 years ago
Read 2 more answers
Please help! i will give brainliest.
kakasveta [241]

Answer:

a) Math and Dance

b) 3 students (Chau, Juan, Ivan)

c) Tome, Jose, Josh, Rita

Step-by-step explanation:

That was so easy homework :-) write in comments if it helped

5 0
2 years ago
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