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2 years ago

A sector with a central angle measure of 200 degrees has a radius of 9cm

Mathematics

1 answer:

Helen [10]2 years ago

3 0

Answer:

B) $45\pi cm^{2}$

Step-by-step explanation:

$A=\frac{\pi r^{2}(central. Angle) }{360} =\frac{\pi (9)^{2}(200) }{360} =\frac{\pi (81)(200)}{360}=45\pi cm^{2}$

Hope this helps

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3 years ago

Jack read 20 pages of a book in 60 minutes. How many pages can he read in 75 minutes at the same rate? Write a proportional equa

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

In a study relating the degree of warping, in mm, of a copper plate (y) to temperature in °C (x), the following summary statisti

elena-14-01-66 [18.8K]

Answer:

y = 0.3035 + 0.0082x

0.6315 mm

x = 23.9634 °C

Step-by-step explanation:

a. Compute the least-squares line for predicting warping from temperature. Round the answers to four decimal places.

We need to find an equation of the form

y = b + mx

where m is the slope and b the Y-intercept.

The slope m can be computed with the formula

$\bf m=\displaystyle\frac{\displaystyle\sum_{i=1}^n(x_i-\bar x)(y_i-\bar y)}{\displaystyle\sum_{i=1}^n(x_i-\bar x)^2}$

Replacing the values in our formula (we will round at the end of the calculations)

$\bf m=\displaystyle\frac{806.94}{98,775}=0.008169476$

the Y-intercept b is computed with the formula

$\bf b=\bar y-m\bar x$

therefore we have

$\bf b=0.5188-0.008169476*26.36=0.303452613$

and the least-squares line rounded to 4 decimals would be

y = 0.3035 + 0.0082x

b. Predict the warping at a temperature of 40°C. Round the answer to three decimal places.

We simply replace x with 40 to get

y = 0.3035 + 0.0082*40 = 0.6315 mm

c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places

Here, we replace y with 0.5 and solve for x

0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>

x = 23.9634 °C

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3 years ago