Since all the angles are congruent, the sides must be congruent too.
So, just have one equation on one side equal to another.
5x= 3x+6
Subtract 3x from both sides.
2x=6
Divide 2 into both sides.
x=3.
We can check this by seeing if all the sides are the same.
5(3)= 15
6(3)-5= 15
3(3)+6= 15
I hope this helps!
~cupcake
Let
x---------> first positive integer
x+1------> second positive integer
x+2-----> third positive integer
we know that
(x+1)*(x+2)=72-------> x² +2x+x+2=72 -------> x² +3x-70=0
using a graph tool-------> <span>I solve the quadratic equation
</span>see the attached figure
the roots are
x1=-10
x2=7
the answer is
first positive integer is x=7
second positive integer is x+1=8
third positive integer is x+2=9
Answer:
d
Step-by-step explanation:
Answer:
3. r = -8
4. x = -5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
2(-5r + 2) = 84
<u>Step 2: Solve for </u><em><u>r</u></em>
- Divide 2 on both sides: -5r + 2 = 42
- Subtract 2 on both sides: -5r = 40
- Divide -5 on both sides: r = -8
<u>Step 3: Check</u>
<em>Plug in r into the original equation to verify it's a solution.</em>
- Substitute in <em>r</em>: 2(-5(-8) + 2) = 84
- Multiply: 2(40 + 2) = 84
- Add: 2(42) = 84
- Multiply: 84 = 84
Here we see that 84 does indeed equal 84.
∴ r = -8 is a solution of the equation.
<u>Step 4: Define equation</u>
264 = -8(-8 + 5x)
<u>Step 5: Solve for </u><em><u>x</u></em>
- Divide both sides by -8: -33 = -8 + 5x
- Add 8 to both sides: -25 = 5x
- Divide 5 on both sides: -5 = x
- Rewrite: x = -5
<u>Step 6: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
- Substitute in<em> x</em>: 264 = -8(-8 + 5(-5))
- Multiply: 264 = -8(-8 - 25)
- Subtract: 264 = -8(-33)
- Multiply: 264 = 264
Here we see that 264 does indeed equal 264.
∴ x = -5 is a solution of the equation.
-28.403 i believe that’s right but idk
