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Aleksandr-060686 [28]
3 years ago
13

2(log 18 - log 3) + = 2log 1/16

Mathematics
1 answer:
Semmy [17]3 years ago
4 0
What do you need?

2log 3/8

= -0.85
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(34 - 6) =(24-1) is...?
Alex

Answer:

34-6 and 24-1 are not equal to each other

Step-by-step explanation:

(34-6)=(24-1)

28 is not equal to 23

4 0
3 years ago
Amjed has 223 cards in his trading card collection. Latif has
Nata [24]

Answer:

The orders of magnitude are numbers of the form:

10^n

where n can be any integer number.

So we can write something like:

"A is n orders of magnitude above B

Now we have the quantities:

Amjed cards = 223

Latif cards = 8741

We want to find how many times more trading cards does Latif  have than Amjed.

Then we need to look at the quotient between the number of cards of Latif and Amjed.

8741/223 = 39.2

Now we need to approximate this to the nearest 10^n number.

(..., 0.1, 1, 10, 100, 1000, ...)

The nearest one to 39.2 is 10.

So we can say that Latif's collection is 10.

and 10 = 10^1

then n = 1

Then we can say that Latif's collection is one order of magnitude above Amjed's collection.

5 0
3 years ago
The petersons have two dogs princess and duke .princess eats 2/3of a bag of dog food in a moth duke eats 7/8 of a bag of dog foo
vesna_86 [32]

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d1i1m1o1n [39]

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45

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6 0
4 years ago
an insect population grows at a rate of 25% per year.if its initial population is 4.2 million what will be its population in thr
marusya05 [52]

The population after 3 years would be 8.20 millions.

Step-by-step explanation:

Given,

Initial population = I = 4.2 million

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If the initial population and growing rate is given, the formula to calculate the population (x) after n years would be:

x = I * (1 + \frac{r}{100} )^{n}

By putting the values in the equation, we get

x = 4.2 * (1 + \frac{25}{100} )^{n}

The population after 1st year (x1) would be

x1 = 4.2 * (1 + \frac{25}{100} )^{1}

x1 = 5.25 million

Similarly,

x2 = 4.2 * (1 + \frac{25}{100} )^{2}

x2 = 6.56 million

x3 = 4.2 * (1 + \frac{25}{100} )^{3}

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4 years ago
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