Answer:
25
Step-by-step explanation:
(6^2+4)−15
(36+4)−15
40−15
25
Answer:
8
Angle 1= RQS and STU
Angle 2= RSQ and TSU
Similar due to Angle Angle
9
15:24
15x=7
24x= 7/15*14= 11.2
10.
10:2
15=10x
2x=3
11.
20:8
8x=10
x=5/4
15-4-5=5/4.
Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
