The distance between -5 and 3 on the number line can be found by which expression?
1 answer:
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Answer:
Length = 49.5 unit and width = 49.5 unit
Step-by-step explanation:
Given as , Perimeter of rectangle = 198 unit
so ,as Perimeter of rectangle = 2× ( Length + width)
Or, 198 = 2 × (Length + width)
Or, = length + width
So, length + width = 99 unit
Now to make area maximum
Length × width = maximum
Or, (99 - width ) × width = maximum
99 Width - width² = maximum Let width = W
Now differentiate both side with respect to W
D(99W - W²) = 0 as, constant diff is 0
So, 99 - 2w = 0
Or, w =
Or, w = 49.5 unit and L = 99- 4905 = 49.5 unit Answer
Answer:
The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>
Step-by-step explanation:
Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.
We have to find the sum of the squares of two numbers whose difference and product is given using given identity,
Since, given the difference of the squares of the numbers is 5 that is
And the product of the numbers is 6 that is
Using identity, we have,
Substitute, we have,
Simplify, we have,
Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169