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sergij07 [2.7K]
2 years ago
8

What is the full number of 2.2300745e56?

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
3 0

Answer:

2 23000745000000000000000000000000000000000000000000000000        ( if I counted correctly !)

Step-by-step explanation:

It is really big ....move the decimal to the right  56 places

  the e  means exponent    2.2300745 x 10^56

You might be interested in
In the inequality "y is less than or equal to 5 and is greater than or equal to -2," the product of the endpoints will be which
Licemer1 [7]

Answer:

  • (C) negative

Step-by-step explanation:

<u>Inequality "y is less than or equal to 5 and is greater than or equal to -2":</u>

  • - 2 ≤ y ≤ 5

<u>This is the interval:</u>

  • y ∈ [- 2, 5]

<u>The endpoints are:</u>

  • - 2 and 5

<u>Product of the endpoints:</u>

  • - 2 × 5 = - 10

<u>Answer choices:</u>

  • (A) odd ⇒ False, - 10 is even
  • (B) positive ⇒ False, - 10 is not positive
  • (C) negative ⇒ True
  • (D) None of the above​ ⇒ False, option C is correct
3 0
2 years ago
Read 2 more answers
Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
2 years ago
HELLLLLLLLLLLLLLP PLLLLLLLSSS, I NEED HELP WITH THIS ANSWER
vlabodo [156]
It would be -4, and 9.2 because they sign is saying that x is less than or equal too 11.
8 0
3 years ago
Read 2 more answers
15.5 × [(2 × 2.4) + 3.2] – 16
ch4aika [34]

Answer:

108

Step-by-step explanation:

5 0
3 years ago
Can someone explain the steps to finding the perimeter of a semi-circle? I didn't really understand it during class. Thanks
andriy [413]
We know that the perimeter of a cylinder is 2πr we will find it as we do always. The perimeter will be :
2 pi r
= 2 pi * 20
= 40 pi
Because it says rounded to the nearest tenth the answer will be : 125.6 cm^3
Because we have a half of a cylinder we will just divide the answer we got by 2:
125.6cm^3 /2 =62.8
The answer is 62.8 cm^3
6 0
2 years ago
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