Ask question

Ask question

All categories

3 years ago

7

We want to place a bench measuring 7.05 feet in the center of a platform that is 40.75 feet long

1 answer:

AnnyKZ [126]3 years ago

5 0

40.75 - 7.05= 33.7
33.7 / 2 = 16.85
16.85 ft. should be on each side of the 7.05 ft. bench

You might be interested in

7 times 10 to the -7 power

klasskru [66]

Answer:

0.0000007 as a regular notation

or 7x10^-7 as scientific notation

3 0

2 years ago

What is the value of<br> –4.00<br> –0.25<br> 1.51<br> 2.41

soldier1979 [14.2K]

For this case we must resolve the following expression: $log_ {0.5} (16)$

We have to:

$log_ {a} (x) = \frac {log_ {b} (x)} {log_ {b} (a)}$

The base change rule can be used if a and b are greater than 1 and are not equal to x.

We substitute the values in the base change formula, using $b = 10$

$\frac {log (16)} {log (0.5)} = - 4$

Answer:

-4

Option A

7 0

3 years ago

What is 1+1? lol i know it’s 2

bogdanovich [222]

Lol I'll just comment to get 5 points

7 0

3 years ago

1. What is the solution of n² – 49 = 0? (1 point)

maks197457 [2]

Answer:

1. $n=\pm7$

2. $x=\pm7i[tex]3.[tex]\pm 12x =a$

4. 22

Step-by-step explanation:

1. $n^2 - 49 = 0$

$n^2 =49$

$n= \sqrt{49}$

$n=\pm7$

2. $x^2+64 = 0$

$x^2 =-64$

$x= \sqrt{49}$

$x=\pm7i[tex]3. Area of square = [tex]a^{2}$

Where a is the side

We are given an area o square = $144x^{2}$

So, $144x^{2}=a^{2}$

$\sqrt{144x^{2}}=a$

$\pm 12x =a$

4. We are given that the solution of quadratic equation -9 and 9

So, equation becomes:

$(x+9)(x-9)=0$

$x^2- 81=0$

So, in the given equation $x^2 + z = 103$

z should be the number from which if we subtract 103 so we get 81

Substitute z = 22

$x^2 + 22 = 103$

$x^2 + 22 -103=0$

$x^2 -81=0$

Thus the value of z is 22

8 0

3 years ago

Read 2 more answers

Write the equation of the vertical line that contains (5,-4)

swat32

The answer is y=5x-4

3 0

2 years ago