Answer:
$9327
Step-by-step explanation:
Apparently, the cost function is supposed to be ...
C(x) = 0.4x^2 -112x +17167
This can be rewritten to vertex form as ...
C(x) = 0.4(x^2 -280) +17167
C(x) = 0.4(x -140)^2 +17167 -0.4(19600)
C(x) = 0.4(x -140)^2 +9327
The vertex of the cost function is ...
(x, C(x)) = (140, 9327)
The minimum unit cost is $9327.
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<em>Comment on the question</em>
You found the number of units that result in minimum cost (140 units), but you have to evaluate C(140) to find the minimum unit cost.
Answer:
C
Step-by-step explanation:
We are given that FGH is a triangle, which means that...
Angle F + Angle G + Angle H = 180
Start by substituting the given angle measurements into the equation:
4x+2+13x-7+3x+5=180
Combine like terms
20x=180
Divide both sides by 20 to isolate x
x=9
Plug 9 back in for x to solve for each angle
Angle F = 4(9)+2=36+2=38
Angle G = 13(9)-7=117-7=110
Angle H = 3(9)+5=27+5=32
Step-by-step explanation:
In this case we have:
Δx = 3/n
b − a = 3
a = 1
b = 4
So the integral is:
∫₁⁴ √x dx
To evaluate the integral, we write the radical as an exponent.
∫₁⁴ x^½ dx
= ⅔ x^³/₂ + C |₁⁴
= (⅔ 4^³/₂ + C) − (⅔ 1^³/₂ + C)
= ⅔ (8) + C − ⅔ − C
= 14/3
If ∫₁⁴ f(x) dx = e⁴ − e, then:
∫₁⁴ (2f(x) − 1) dx
= 2 ∫₁⁴ f(x) dx − ∫₁⁴ dx
= 2 (e⁴ − e) − (x + C) |₁⁴
= 2e⁴ − 2e − 3
∫ sec²(x/k) dx
k ∫ 1/k sec²(x/k) dx
k tan(x/k) + C
Evaluating between x=0 and x=π/2:
k tan(π/(2k)) + C − (k tan(0) + C)
k tan(π/(2k))
Setting this equal to k:
k tan(π/(2k)) = k
tan(π/(2k)) = 1
π/(2k) = π/4
1/(2k) = 1/4
2k = 4
k = 2
Area= 1/2(base)(height)
A= 1/2(7)(2)
A= (1*2*7)/2
A= 14/2
A= 7 units squared
Hope this helps! :)
Answer : 7,889
Hundreds digit : 800
Tens digit : 80
800 ÷ 80 = 10 (800, the hundreds digit, is 10 times as great as the tens digit, 80)
