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belka [17]
1 year ago
6

If 0.8Vx160=0.9Vx45 Get the value of V

Mathematics
1 answer:
Irina-Kira [14]1 year ago
3 0

Answer:

V=0

Hope it helps

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Step-by-step explanation:

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From decimal to fraction: Rewrite the decimal number number as a fraction (example: <span>2.625=<span>2.6251</span></span>) an then Multiply by 1 to eliminate 3 decimal places, we multiply numerator and denominator by 10 cubed = 1000<span><span><span>2.625/1</span>×<span>1000/1000</span>=<span>2625/1000 and don forget to reduce if possible;)

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In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the
oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

\mu = 503, \sigma = \sqrt{9604} = 98

So

Z = \frac{X - \mu}{\sigma}

1.476 = \frac{X - 503}{98}

X - 503 = 1.476*98

X = 648

Abby's score

She scored 648.

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So

Z = \frac{X - \mu}{\sigma}

Z = \frac{648 - 521}{101}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

The percentle for Abby's score was the 89.62nd percentile.

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3 years ago
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