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Nonamiya [84]
2 years ago
13

Solve the following inequality. Negative one-half p less-than negative 16 Which graph shows the correct solution? A number line

going from 27 to 37. An open circle is at 32. Everything to the right of the circle is shaded. A number line going from 27 to 37. An open circle is at 32. Everything to the left of the circle is shaded. A number line going from 3 to 13. An open circle is at 8. Everything to the left of the circle is shaded. A number line going from 3 to 13. An open circle is at 8. Everything to the right of the circle is shaded. answer gets brainleist
Mathematics
1 answer:
ratelena [41]2 years ago
8 0

The answer will be A number line going from 27 to 37. An open circle is at 32. Everything to the right of the circle is shaded.

<h3>What is inequality?</h3>

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than’, or < ‘less than’.

We have an expression of inequality:-

(-1/2)p < -16

p > 32 . . . . . . multiply by -2; this reverses the inequality symbol

The open circle will be at 32; the line will be shaded for higher values (to the right).

Hence the answer will be A number line going from 27 to 37. An open circle is at 32. Everything to the right of the circle is shaded.

To know more about inequality follow

brainly.com/question/24372553

#SPJ1

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Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

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Step-by-step explanation:

The equation:

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We know that the initial height is the height when t = 0s

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h(t) = 0

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When do you hit the water?

Here we just need to find the value of t such that:

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Using the Bhaskara's formula, we get:

t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}

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The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

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What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

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Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

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