Answer:
Tipo de enlace enlace en CO2 - Covalente
Tipo de enlace enlace en KCl - iónico
Tipo de enlace enlace en H2O: enlaces covalentes y de hidrógeno
Electronegatividad de CO2 - Diferencia en electronegatividad de carbono (EN = 2.5) y oxígeno (EN = 3.5) = 3.5 - 2.5 = 1
Diferencia en electronegatividad de KCl = 3,2 -0,8 = 2,4
Diferencia en electronegatividad de H2O = 3.5 -2.1 = 1.4
Explanation:
Tipo de enlace enlace en CO2 - Covalente
Tipo de enlace enlace en KCl - iónico
Tipo de enlace enlace en H2O: enlaces covalentes y de hidrógeno
Electronegatividad de CO2 - Diferencia en electronegatividad de carbono (EN = 2.5) y oxígeno (EN = 3.5) = 3.5 - 2.5 = 1
Diferencia en electronegatividad de KCl = 3,2 -0,8 = 2,4
Diferencia en electronegatividad de H2O = 3.5 -2.1 = 1.4
<span>The question is asking us "Which of the following would be a result of increased solar activity?"
The Sun is extremely hot, and when it is warm on Earth, the heat has as it source in the Sun. Therefore, an increased solar activity would mean increased temperature on Earth - longer summers and shorter winters, and warmer sea temperatures. The best answer is :
B. Warmer-than-normal sea surface temperatures </span>
Answer:
A cation is formed when a metal ion loses a valence electron while an anion is formed when a non-metal gains a valence electron. They both achieve a more stable electronic configuration through this exchange.
Answer:
The limiting reacting is O2
Explanation:
Step 1: data given
Number of moles O2 = 21 moles
Number of moles C6H6O = 4.0 moles
Step 2: The balanced equation
C6H6O + 7O2 → 6CO2 + 3H2O
Step 3: Calculate the limiting reactant
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
O2 is the limiting reactant. It will completely be consumed (21 moles).
C6H6O is in excess.
For 7 moles O2 we need 1 mol C6H6O
For 21 moles O2 we'll need 21/7 = 3 moles C6H6O
There will remain 4.0 - 3.0 = 1 mol C6H6O
Step 4: calculate products
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
For 21 moles O2 we'll have 6/7 * 21 = 18 moles CO2
For 21 moles O2 we'll have 3/7 * 21 = 9 moles H2O
The limiting reacting is O2
This is percent composition
The formula for that is
(Mass of part/total mass) x 100
What’s the total molar mass of CO2?
12.01 +16(2) = 44.01 g/mol
What is the molar mass of Carbon?
Since there is only one carbon it is 12.01 g/mol
(12.01/44.01) x 100 = 27.29%