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Helga [31]
3 years ago
11

How do anion formation and valence electrons relate?

Chemistry
2 answers:
vagabundo [1.1K]3 years ago
7 0

Answer:

A cation is formed when a metal ion loses a valence electron while an anion is formed when a non-metal gains a valence electron. They both achieve a more stable electronic configuration through this exchange.

Genrish500 [490]3 years ago
6 0

Answer:

A cation is formed when a metal ion loses a valence electron while an anion is formed when a non-metal gains a valence electron. They both achieve a more stable electronic configuration through this exchange.

Explanation:

Hope I helped!

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How many moles of oxygen are in 52.5 grams of oxygen gas?
adell [148]
An oxygen gas is a diatomic molecule which means that each molecule is composed of 2 atoms. Its symbol is O2. 

Each oxygen atom has a molar mass of 16 g/mol. The molar mass of oxygen gas is calculated below,
                         molar mass = 2 x (16 g/mol) = 32 g/mol

To determine the number of moles in 52.5 grams of oxygen, divide the given mass by the calculated molar mass.
 
                                 n = 52.5 grams / (32 gram/ mol)
                                     n = 1.64 moles

Thus, there are 1.64 moles of oxygen gas. 
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3 years ago
Compare the function of a switch in an electric circuit to the function of a water faucet. How are they different?
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They both turn something on, and the way they are different is the way they turn it off<span>
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3 years ago
All of the following are true of bases except
Oksana_A [137]
All of these are correct except the first option, as Arrhenius bases increase the concentration of hydroxide ions.
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3 years ago
Read 2 more answers
A sample of 1L of gas in a container at-73C has a pressure of 32.2inHg. To
Goryan [66]

Answer:

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Explanation:

8 0
3 years ago
How many moles of dinitrogen monoxide are present in 9.3 x 10^22 molecules of this compound?
Step2247 [10]

Answer:

<h2>0.15 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities.

From the question we have

n =  \frac{9.3 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.154485...

We have the final answer as

<h3>0.15 moles</h3>

Hope this helps you

8 0
3 years ago
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