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alex41 [277]
2 years ago
10

At the fast food restaurant, an order of fries costs $1.05 and a drink costs $1.07. How much would it cost to get 3 orders of fr

ies and 4 drinks? How much would it cost to get ff orders of fries and dd drinks?
Total cost, 3 orders of fries and 4 drinks:

Total cost, ff orders of fries and dd drinks:
Mathematics
1 answer:
trasher [3.6K]2 years ago
5 0

Answer:

$7.43

Step-by-step explanation:

f (fries) = 1.01

d (drinks) = 1.07

1.05f + 1.07d = ?

To solve this problem, you need to replace the variable with the amount of each item.

1.05(3) + 1.07(4) = ?

Now we can solve by multiplying and adding:

3.15 + 4.28 = ?

<u>7.43</u>

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The graph represents function 1, and the equation represents function 2:
inessss [21]

Answer:

Option D.

Step-by-step explanation:

The slope of a horizontal line is 0.

It is given that the function 1 is a horizontal line that passing through the y-axis at y = 4.

It means the rate of change of function 1 is 0.

The slope intercept form of a linear function is  1

where, m is slope and b is y-intercept.

The function 2 is  2

On comparing (1) and (2), we get

The rate of change of function 2 is 8.

The difference between rate of change is

The rate of change of function 2 is 8 more than the rate of change of function 1.

Therefore, the correct option is D.

3 0
3 years ago
Read 2 more answers
Which expression and could you explain
docker41 [41]
I would say d. Hope that helps
4 0
3 years ago
Read 2 more answers
let a = (a1, a2) and b = (b1, b2) and c = (c1,c2) be three non zero vectors. if a1b2 - a2b1 is not equal to 0. then show three a
Ksenya-84 [330]

Consider the contrapositive of the statement you want to prove.

The contrapositive of the logical statement

<em>p</em> ⇒ <em>q</em>

is

¬<em>q</em> ⇒ ¬<em>p</em>

In this case, the contrapositive claims that

"If there are no scalars <em>α</em> and <em>β</em> such that <em>c</em> = <em>α</em><em>a</em> + <em>β</em><em>b</em>, then <em>a₁b₂</em> - <em>a₂b₁</em> = 0."

The first equation is captured by a system of linear equations,

\begin{cases}c_1 = \alpha a_1 + \beta b_1\\ c_2 = \alpha a_2 + \beta b_2\end{cases}

or in matrix form,

\begin{pmatrix}c_1\\c_2\end{pmatrix} = \begin{pmatrix}a_1&b_1\\a_2&b_2\end{pmatrix}\begin{pmatrix}\alpha\\\beta\end{pmatrix}

If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be

\begin{vmatrix}a_1&b_1\\a_2&b_2\end{vmatrix} = a_1b_2-a_2b_1 = 0

and this is what we wanted to prove. QED

3 0
3 years ago
X^2 + 18x + c = 25 +c
svet-max [94.6K]
Rearrange to: x^2 + 18x - 25 = 0
Then factorise (I like to do it by completing the square):
(x + 9)^2 -81 -25 = 0
(x + 9)^2 = 106
x + 9 = sqrt(106)
The sol'ns are:
x = -9 + and - sqrt(106)
7 0
3 years ago
2/6 +36 Whats the answer ?​
777dan777 [17]

36 2/6

do I have to explain???

4 0
2 years ago
Read 2 more answers
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