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sergey [27]
2 years ago
14

Find the slope of the line that passes through (64, -7) and (54, 67).

Mathematics
2 answers:
Korolek [52]2 years ago
4 0

Answer:

-37/5 because you subtrace both y values on the numerator to get 74 and on the bottom you do the same for x and get -10 and then you simplify to get -37/5

rjkz [21]2 years ago
3 0
The slope is -37/5

Hope this helps!
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Having Problems With This Question
hjlf

Answer:

f+g(2)=10

f-g(4)=-4

F/G(2)= 7/3

(f)(g)(1)=0

Step-by-step explanation:

1. (f+g)=2x+3+x^2-1 2(2)+2=10

2. (f-g)=(2x+3)-(x^2-1)=-x^2+2x+4= -16+8+4=-4

3. f/g= 2x+3/x^2-1 4+3/3= 7/3

4. f*g= (2x+3)(x^2-1)= 2x^3+3x^2-2x-3= 2(1)^3-2(1)+3(1)^2-3=0

8 0
2 years ago
Please help y - (-10) = 12 <br> y = ______
kotykmax [81]
Subtracting a negative means that you will add the number. Convert the symbols to get the following:

y + 10 = 12

Subtract 10 from both sides.

y = 2


3 0
3 years ago
Amy has 120 acres of peanuts. She risked the soil using a 16-foot disk traveling 4.2 miles per hour.she used 0.62 gallon per acr
lesya [120]
Where is the question?????
3 0
3 years ago
Suppose the length of each side of a square is increased by 5 feet.if the perimeter of the square is now 56 feet.what were the o
skelet666 [1.2K]
We can find the length of the sides now by dividing 56 by 4, which gives us 19.  Subtracting 5 from 19 gives us our answer of 14 feet.
7 0
3 years ago
what is te discontinuity of the function f(x) = the quantity of x squared plus 6x plus 8 all over x plus 4?
seropon [69]

Answer:

A hole at x=-4.

Step-by-step explanation:

This is a fraction so we have to worry about division by zero.

The only time we will be dividing by 0 is when x+4 is 0.

Solving the equation

x+4=0 for x:

Subtract 4 on both sides:

x=-4

So there is either a vertical asymptote or a hole at x=-4.

These are the kinds of discontinuities we can have for a rational function.

If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.

If is is a vertical asymptote, x=-4 will make the top NOT zero.

Let's see what -4 for x in x^2+6x+8 gives us:

(-4)^2+6(-4)+8

16+-24+8

-8+8

0

Top and bottom are 0 when x=-4.

Let's see what happens after simplication.

We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.

So what 2 numbers together multiply to be 8 and add up to be 6.

I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.

\frac{x^2+6x+8}{x+4}=\frac{(x+4)(x+2)}{x+4}=x+2

We we able to cancel out that factor that was giving us x=-4 is a zero.  

Therefore there is a hole at x=-4.

7 0
3 years ago
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