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Over [174]
2 years ago
12

The cuboid has dimension 25cm by 10cm by 8cm the volume is​

Mathematics
1 answer:
sdas [7]2 years ago
6 0

2000cm³.

The volume of any 3d shape is the length x height x width.

This case it is 25 x 10 x 8.

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Molly had a balance of $72 In her savings account before depositing $25. What is her new balance?
vovangra [49]

Answer:

$97

Step-by-step explanation:

just add 72 and 25 dude

4 0
3 years ago
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
A person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen he sells it at Rs 80 a pair find the gain p
marusya05 [52]

Answer:

33.33%

Step-by-step explanation:

We need to calculate the <u>unit selling price and cost of each cosmetics.</u>

If a person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen., then for 1 cosmetics, we will say;

x = 1 cosmetic

since 360 = 12 cosmetic

cross multiply

12x = 360

x = 360/12

x = 30

Hence the unit cost price of the cosmetics will be Rs. 30

Similarly, if he sells it at Rs 80 a pair, then he sold one cosmetic at 80/2 = Rs. 40 (a pair is 2 cosmetics)

Selling price per unit = Rs. 40

Cost price per unit = Rs. 30

percent gain = SP-CP/CP * 100%

percent gain = 40-30/30 * 100

percent gain = 10/30 * 100

percent gain = 100/3

percent gain = 33.33%

Hence the percentage gain is 33.33%

5 0
3 years ago
What s the Lcm of 4 and 9
Likurg_2 [28]
The LCM for 4 and 9 is 36
8 0
3 years ago
Read 2 more answers
What is the answer please help!!!!!
insens350 [35]
What is the question please help!
6 0
3 years ago
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