The vertex is (3,0). The 3 inside the abs val bar tells you the x value of the vertex is 3. No number outside the abs value bar is a +0 which is the y value of the vertex.

4 0

2 years ago

What is the value of m, if the equation my2+2y−4=0 has exactly one root?

stich3 [128]

Answer:

$m=\frac{-1}{4}$

Step-by-step explanation:

A quadratic equation has one root if the discriminant is 0.

That is we need $b^2-4ac=0$ for this particular question.

Compare the following to find $a,b, \text{ and } c$ :

$ax^2+bx+c=0$

$my^2+2y-4=0$

The variable $x$ is representative of the variable $y$ here.

$a=m$

$b=2$

$c=-4$

Plug in into $b^2-4ac=0$ :

$(2)^2-4(m)(-4)=0$

$4+16m=0$

Subtract 4 on both sides:

$16m=-4$

Divide both sides by 16:

$m=\frac{-4}{16}$

Reduce:

$m=\frac{-1}{4}$

6 0

2 years ago

Read 2 more answers

PLEASE ANSWER ASAP!!!

Vesna [10]

Answer:

C=x (x+3)

Step-by-step explanation:

x cannot divide x+3 definitely so the denominators must be multiplied to get the least common denominator.

4 0

3 years ago