Answer:
Step-by-step explanation:
y = 3x - 5
y = 1/3x + 3
3x - 5 = 1/3x + 3....multiply everything by 3 to get rid of the fraction
9x - 15 = x + 9
9x - x = 9 + 15
8x = 24
x = 24/8
x = 3
y = 3x - 5
y = 3(3) - 5
y = 9 - 5
y = 4
solution is : x = 3 and y = 4...or (3,4) <==
Answer:
Choice (C): x=0, x=-1 with multiplicity of 2
Step-by-step explanation:
Y = 5x - 13 ----------- (1)
5x + 2y = 19 --------- (2)
Sub (1) into (2):
5x + 2(5x -13) = 19
5x + 10x - 26 = 19
15x = 19 + 26
15x = 45
x = 3 -------- sub back into (1)
y = 5(3) - 13
y = 15 - 13
y = 2
Ans: x = 3, y = 2
Answer:
Step-by-step explanation:
Given that a certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office.
The company can assign I employee to any one of 2 office i.e. in 2 ways
Similarly can assign II employee also in 2 ways and III in two ways.
Total no of ways = 2x2x2 = 8
There are 8 ways the company can assign 3 employees to 2 different offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office
