In standard form,it should be 0 +0.9 +0.05
<span>Because G is the centroid of the triangle, therefore
AG = 2GF
That is,
5x + 4 = 2(3x - 1)
5x + 4 = 6x - 2
4 + 2 = 6x - 5x
6 = x
Therefore
AG = 5*6 + 4 = 34
GF = 3*6 - 1 = 17
A.F = AG + GF = 34 + 17 = 51
Answer: 51</span>
Answer:
16.35Rs would be paid by everyone.
Step-by-step explanation:
98.10/6
=16.35Rs would be paid by everyone.
Hope it will help you :)
Let's use K for Kona and F for Fuji. The system of equations has to be a balanced system. For example, you can't mix the number of pounds of beans with the cost for each because pounds and dollars are different and you can only combine like terms...pounds with pounds and dollars with dollars. So let's start with the number of pounds. Since we don't know how much of each he bought we have the 2 unknowns, F and K, but we DO know that he bought 23 pounds total. So the first equation is
K + F = 23
Now let's see what we can do with the dollars. Again, we don't know how much he bought of each kind of coffee, but we do know that Kona beans cost $11 per pound and that Fuji beans cost $7.50 per pound, and we know that he spent a total of $197. So let's set that up:
11K + 7.50F = 197
Those are your 2 equations. It doesn't say you need to solve them, so you're done.
Answer:
B: II, IV, I, III
Step-by-step explanation:
We believe the proof <em>statement — reason</em> pairs need to be ordered as shown below
Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC — given
Draw Line segment BE Draw Line segment FC — by Construction
Point G is the point of intersection between Line segment BE and Line segment FC — Intersecting Lines Postulate
Draw Line segment AG — by Construction
Point D is the point of intersection between Line segment AG and Line segment BC — Intersecting Lines Postulate
Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH — by Construction
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II Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC — Midsegment Theorem
IV Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC — Substitution
I BGCH is a parallelogram — Properties of a Parallelogram (opposite sides are parallel)
III Line segment BD ≅ Line segment DC — Properties of a Parallelogram (diagonals bisect each other)
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Line segment AD is a median Definition of a Median