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2 years ago

How many aluminum atoms are there in 3.50 grams of al2o3?

SAT

1 answer:

kifflom [539]2 years ago

3 0

Answer:

4.13×10^22 atoms

Explanation:

1. Find number of moles

mole=mass/rmm of compound

mole= 3.50/102

mole= 7/204 mol

2. Multiply it with avagadros constant( 6.02×10^23 particles)

7/204 × 6.02×10^23= 2.0657×10^22

3. Multiply it with the number of ALMINIUM ATOMS IN AL203( which is 2 atoms)

2.0657×10^22 × 2

you get 4.13×10^22 atoms

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The patients are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

The parameters are:

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--------------------

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The probability is 0.845 = 84.5%.

A similar problem is given at brainly.com/question/24008577

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