Based on the calculations, the solubility of PbCrO₄ in water at at 25°C is equal to 1.4 x 10⁻⁸ M.
<h3>How to calculate the solubility of PbSO₄?</h3>
The properly balanced chemical equation for the dissociation of PbSO₄ is given by:
PbCrO₄(s) ⇆ Pb²⁺(aq) + CrO₄²⁻(aq)
Initial 0 0
Change +x +x
Equib. conc. x x
<u>Note:</u> The Ksp of PbCrO₄ at 25°C is equal to 2.0 × 10⁻¹⁶.
Next, we would set up an equation from the ICE table for its Ksp;
Ksp = [Pb²⁺][CrO₄²⁻]
2.0 × 10⁻¹⁶ = [x][x]
2.0 × 10⁻¹⁶ = x²
x = √2.0 x 10⁻¹⁶
x = 1.4 x 10⁻⁸ M.
Read more on solubility here: brainly.com/question/15396081
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It might be Diverse? Since diverse means showing a great deal of variety
-6y + 11x = -36....multiply by 4
-4y + 7x = -24....multiply by -6
-----------------
-24y + 44x = - 144 (result of multiplying by 4)
24y - 42x = 144 (result of multiplying by -6)
----------------add
2x = 0
x = 0
-4y + 7x = -24
-4y + 7(0) = -24
-4y = -24
y = -24/-4
y = 6
solution is (0,6)
Gravity and would burn up