Question

Please help with 6 and 7

Answer 1

Answer:

6. The number is $-5$

7. The two numbers are $10$ and $11$

Step-by-step explanation:

Question six can be re-worded to create the following expression:

$-2=\frac{4x+10}{5}$

Solve for x to find the number:

$-2=\frac{4x+10}{5}\\-10=4x+10\\-20=4x\\\frac{-20}{4} = x\\-5 = x$

Question seven can be solved by first listing the constraints (assuming x is smaller than y):

1. x and y are less than 20
2. $x + 1 = y$
3. $3x - 8 = 2y$

To get the numbers, we can create a system of linear equations. First, solve for $y$ in each expression:

$y = x+1$

$2y = 3x-8\\y = \frac{3}{2}x - 4$

Solve for $x$:

$x+ 1 = \frac{3}{2}x - 4\\x + 5 = \frac{3}{2}x\\5 = \frac{3}{2}x - x\\5 = \frac{1}{2}x\\10 = x$

Solve for $y$:

$y = x + 1\\y = 10 + 1\\y= 11$

Answer 2

Answer:

see explanation

Step-by-step explanation:

(6)

let n be the number then the sum of 4 times the number and 10 is 4n + 10

so

$\frac{4n+10}{5}$ = - 2 ( multiply both sides by 5 to clear the fraction )

4n + 10 = - 10 ( subtract 10 from both sides )

4n = - 20 ( divide both sides by 4 )

n = - 5

(7)

let the consecutive integers be n and n + 1 , then

3n = 2(n + 1) - 8 ← distribute parenthesis and simplify right side

3n = 2n + 2 - 8

3n = 2n - 6 ( subtract 2n from both sides )

n = - 6 and n + 1 = - 6 + 1 = - 5

the 2 integers are - 6 and - 5