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Anestetic [448]
3 years ago
15

The oil tank in your car is leaking at a rate of 1.2 oz per mile driven. You drove 15 miles over to your grandma's house. How ma

ny cups of oil did your car leak?
Mathematics
2 answers:
belka [17]3 years ago
8 0
2.25 ounces were leaked.
Bumek [7]3 years ago
5 0
The car has leaked out 2.25 cups of oil
You might be interested in
Chris has an account that pays 3.64% simple interest per year and wants to accumulate $3,080 in interest from it over the next 1
Semenov [28]

Answer:

Step-by-step explanation: A=p(1±r%)>t

A=3,080(1+3.64%)>12

=4730. 200

6 0
2 years ago
What is the distributive property of 2(3+6y)
serious [3.7K]

Answer:

6+12y

Step-by-step explanation:

first, distribute the 2 to the parenthesis:

-multiply the 2 to the 3 and 6y

We get 6+12y

hope this helps :)

7 0
3 years ago
What is the value of this expression? 2.4 27.316
Rom4ik [11]

Answer:

If it is 2.4 times 27.316, it is 65.5584

Step-by-step explanation:

7 0
2 years ago
In the equation (m^5/6) (m^1/6)^7 = m^x , what is the value of x that makes the equation true?
vlabodo [156]

{m}^{ \frac{5}{6} }  \times (m {}^{ \frac{1}{6} } ) {}^{7 }  = m {}^{x}

m {}^{ \frac{5}{6} }  \times m {}^{ \frac{7}{6} }  = m {}^{x}

{m}^{ \frac{5 \times 7}{6 \times 6} }  =  {m}^{x}

\frac{35}{36}  = x

6 0
2 years ago
Find the work required to move an object in the force field F = e^x + y (1, 1, z) along the straight line from A(0, 0, 0) to B(-
DENIUS [597]

\vec F(x,y,z)=(e^x+y)(1,1,z)

is conservative if we can find a scalar function f such that \nabla f=\vec F. This would require

f_x=e^x+y

f_y=e^x+y

f_z=(e^x+y)z

Integrating both sides of the first equation wrt x gives

f(x,y,z)=e^x+xy+g(y,z)

Differentiating both sides of this wrt y gives

f_y=x+g_y=1\implies g_y=1-x\implies g(y,z)=y-xy+h(z)

but we assumed g was a function of y and z, independent of x. So there is no such f and \vec F is not conservative.

To find the work, first parameterize the path (call it C) by

\vec r(t)=(1-t)(0,0,0)+t(-4,5,-5)=(-4t,5t,-5t)

for 0\le t\le1. Then

\vec r'(t)=(-4,5,-5)

and the work is given by the line integral,

W=\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1(e^{-4t}+5t,e^{-4t}+5t,-(e^{-4t}+5t)5t)\cdot(-4,5,-5)\,\mathrm dt

W=\displaystyle\int_0^1(125t^2+5t+(25t+1)e^{-4t})\,\mathrm dt=\boxed{\frac{2207}{48}-\frac{129}{16e^4}}

8 0
3 years ago
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