The equations give you information as to where to plot points.
For y = -x + 1, you know the slope is -1, and the line intersects the y-axis at (0, 1). The y-axis is the vertical line; to plot (0, 1), find 1 on the vertical line and mark it. Now, the slope is -1; that means the line will slope downwards. To plot more points, count 1 unit down from (0, 1) and 1 unit to the right. You should end up at (1, 0).Connect those and you have a line.
For y = -2x + 4, the slope is -2 (so it will also slope downwards), and the y-intercept is 4. Find (0, 4) and plot it. The -2 tells you to count 2 units down (instead of 1 like we did for the last equation) and 1 over. That is the second line.
I hope this helps.
Answer:
Step-by-step explanation:
<span>Using the Triangle Inequality Theorem
</span><span>The sum of two side lengths of a triangle is always greater than the third side
</span>
first one: 6, 22 , 10
6 + 22 > 10 : yes
22 + 10 > 6 : yes
6 + 10 > 22 : No because 16 < 22
These 3 lengths could NOT be lengths of sides of a triangle
second one: 8 , 15 , 22
8 + 15 > 22 : yes
15 + 22 > 8 : yes
8 + 22 > 15 : yes
These 3 lengths could be lengths of sides of a triangle
Answer:
Second option
8 cm, 15 cm, 22 cm
9514 1404 393
Answer:
B) -3
Step-by-step explanation:
There are methods for finding only c. Cramer's rule is one of them. It involves finding two determinants and taking their ratio. Here, we choose a more <em>ad hoc</em> approach. It appears that the value of b can be found by combining the last two equations.
(1/2)(2a +4b -2c) -(a -3b -c) = (1/2)(12) -(-4)
5b = 10
b = 2
Now, we can substitute this value into the first two equations. This gives ...
5a +c = -8
a - c = 2
Subtracting 5 times the second from the first gives ...
(5a +c) -5(a -c) = (-8) -5(2)
6c = -18 . . . . simplify
c = -3 . . . . . . divide by 6
The value of c is -3.
Answer:
C. populations are non normal and the sample sizes are large.
Step-by-step explanation:
To test hypotheses about the difference between two populations means we deal with the following three cases.
1) both the populations are normal with known standard deviations.
2)both the populations are normal with unknown standard deviations.
3) both the populations are non normal in which case both the sample sizes are necessarily large.
So option C is the correct answer.
