Question

#83 will give brainliest with best response!​

Answer 1

Answer:

$\frac{31x-159}{168y}$

Step-by-step explanation:

$\frac{x-4}{7y}$ - $\frac{x+7}{8y}$ + $\frac{x+3}{6y}$

the LCD of the denominators is 168y , then

$\frac{24(x-4)-21(x+7)+28(x+3)}{168y}$ ← distribute and simplify numerator

= $\frac{24x-96-21y-147+28x+84}{168y}$

= $\frac{31x-159}{168y}$

Answer 2

Answer:

$\frac{31x - 159}{168y}$

Step-by-step explanation:

First we need to find a common denominator between 7y, 8y, and 6y. And the smallest common denominator is 336y, which I got by multiplying 7*8*6 and since they all share y, we can just keep the y without multiplying it.

Now, we need to multiply each fraction by the correct number on the top and bottom to reach 336. When we do this, we get $\frac{x-4}{7y} (\frac{48}{48} ) - \frac{x+7}{8y}(\frac{42}{42}) + \frac{x+3}{6y}(\frac{56}{56})$. OMG. Well, now we need to expand the numerators...$\frac{48x - 192}{336y} - \frac{42x + 294}{336y} + \frac{56x + 168}{336y} = \frac{62x - 318}{336y}$. Another OMG. But now we need to simplify...so we get $\frac{31x - 159}{168y}$. Done.

Hope this helps! :)