Answer:
x= 2
y= 7
z= 4
Step-by-step explanation:
Equation 1: x+y+z=13
Equation 2: x-z= -2
Equation 3: -2x+y=3
Add equation 2 and 1
(x+y+z)+(x-z)= 13 -2
2x+y= 11
Add this to equation 3
(-2x+y)+(2x+y)= 11+3
2y= 14
y= 7
Plug in y= 7 to equation 3
-2x+(7)= 3
-2x+7=3
-2x= -4
x= 2
Plug x=2 into equation 2
2-z= -2
4 = z
You would do 8 / (2/3).
The answer is 12
The standard equation for a circle with center at (h,k) and radius r is
(x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle.
The formula for the circumference of a circle is C = 2pi*r. In this particular problem, we need to determine the radius of the circle. That radius is: r = C/[2pi]. Here, C = 22pi, so we get r = 22pi/[2pi], and so r^2 = 11^2.
Putting to use the given info, we have:
(x+14)^2 + (y-5)^2 = 11^2
Answer:
the answer is 5 cups
Step-by-step explanation:
let x rep a cup of sugar
and y rep a cookie
and k be constant
x/kx=6y/30y
k=5
74-50 is 24. 24/2 is 12.
your number was 12.
