So we have lengths a and b and are given:
2a+2b = 66 => a+b = 33 => a= 33-b
a*b = 272
plug in one into the other:
(33-b)b = 272 => -b^2 +33b - 272 = 0
Can be factored as (b-16)(b-17) = 0, if you don't "see" this immediately, use the well known abc formula to find b.
So a=16 and b=17 or vice versa.
Answer:
A. The function has three distinct real zeros.
Step-by-step explanation:
Answer: Choice B) 128
Explanation:
We'll add up the given arc measures and then cut the result in half to get the angle formed by the intersecting chords (that subtend the arcs in question).
chord angle = (arc1+arc2)/2
x = (54+202)/2
x = 256/2
x = 128
Answer: 9πcm²
Step-by-step explanation: area of the square= 36cm²
Therefore, the area of one side= √area = √36 = 6cms
Since the circle is touching the sides of the square, the side of the square = the diameter of the circle
Therefore the radius of the circle= side/2 = 3cm
The formula for the ares of the circle is πr²
π*3*3 = 9πcm²
How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?
Answer: the third option (12 zeros..).
Use ^ to denote an exponent..
f(x) = 3x^12 - 17x^8 + 11x^4 - 6x + 23..
We know from that fact that the number of zeros (real or complex) in a polynomial is the same as the degree of the polynomial..
The degree is the greatest/highest power of the terms, which in this case is 12 (since 12 is the greatest exponent..)..
The degree is 12, thus it means there are 12 zero's..
Answer: the third option (12 zero's )...
