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Lapatulllka [165]
3 years ago
10

Shula covered a box with fabric. The dimensions of the box are 7 inches x 11 inches and depth is 8 inches. If fabric costs 7 cen

ts how much will she spend on fabric
Mathematics
1 answer:
natta225 [31]3 years ago
3 0

Answer:

Option (D) is correct.

Shyla spend $30.94 on the fabrics

Step-by-step explanation:

Shyla has a box with the dimensions of 7 inches, 11 inches, 8 inches. Since it has 3 sides thus, it is form of a cuboid.

Here Length (l) = 7 inches

Breadth (b) = 11 inches

Height (h) = 8 inches

Surface area of Cuboid = 2( lb +bh + hl )

Substitute the values, we get,

Surface area of Cuboid = 2( 7 × 11 + 11× 8 + 7 × 8 )

                                       = 2( 77 +88 +56)

                                       = 422 square inches.

Given: the fabric costs 7 cents per square inch = $0.07 per square inches.

Money  Shyla spend on the fabric = total area × cost of fabric per square inch

                                                      = 442 × 0.07

                                                      = $30.94

Thus,  Shyla spend $30.94 on the fabrics.

So , Option (D) is correct.

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M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
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Answer:

Step-by-step explanation:

Given

<LON = 77°

<LOM = (9x+44)°

<MON = (6x+3)°

The addition postulate is true for the given angles since tey have a common point O:

<LON = <LOM+<MON

Since we are not told what to find we can as well look for the value of x, <LOM and <MON

Substitute the given parameters and get x

77 = 9x+44+6x+3

77 = 15x+47

77-47 = 15x

30 = 15x

x = 30/15

x = 2

Get <LOM:

<LOM = 9x+44

<LOM = 9(2)+44

<LOM = 18+44

<LOM = 62°

Get <MON:

<MON = 6x+3

<MON = 6(2)+3

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<MON = 15°

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