Sorry I can not help u right now
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
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<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
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<span>I hope this helps! </span>
Answer: Use the PEMDAS rule
Step-by-step explanation: 0z+3z+5=2(z-3)=
z= -1
you need to do the z numbers all together and the normal numbers together then subtract them to get -1
I hope that I help you
1,000,000
If the number is 5-9 (in this case, the one in the hundred-thousands place), you round up. If lower, then round down
multiply 6 x 6 to get 36 and 7 x 11 to get 77.
6/7 x 6/11 = 36/77
