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vovikov84 [41]
3 years ago
9

M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,

x, plus, 44, degrees \qquad m \angle MON = 6x + 3^\circm∠MON=6x+3 ∘ m, angle, M, O, N, equals, 6, x, plus, 3, degree
Mathematics
1 answer:
timama [110]3 years ago
6 0

Answer:

Step-by-step explanation:

Given

<LON = 77°

<LOM = (9x+44)°

<MON = (6x+3)°

The addition postulate is true for the given angles since tey have a common point O:

<LON = <LOM+<MON

Since we are not told what to find we can as well look for the value of x, <LOM and <MON

Substitute the given parameters and get x

77 = 9x+44+6x+3

77 = 15x+47

77-47 = 15x

30 = 15x

x = 30/15

x = 2

Get <LOM:

<LOM = 9x+44

<LOM = 9(2)+44

<LOM = 18+44

<LOM = 62°

Get <MON:

<MON = 6x+3

<MON = 6(2)+3

<MON = 12+3

<MON = 15°

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Factor –7x3 21x2 3x – 9 by grouping. what is the resulting expression?
MakcuM [25]

The resulting expression on factorization by grouping method is (3-7x²)(x-3).

<h3>What is Factorization?</h3>

Factorization is a method in which an Integer or an expression is written in terms of product of its fractions.

The expression given in the question is

–7x³ + 21x² + 3x – 9

This equation has to be factorized using grouping method.

group of two or more is formed and common term is taken out.

-7x² (x -3) +3(x-3)

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The resulting expression on factorization by grouping method is

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2 years ago
Find the least number by which 243 must be divided to make it a perfect<br> square.
yaroslaw [1]

Answer:

Step-by-step explanation:

  • Well I hate to break the news but 243 is not a perfect square. I'll work you through it, 243 is not a perfect square because it is not an even number. an even number must end in (0,2,4,6,8)
  • Step one. Find the square root. the square root of 243 is <em>15.588. </em>
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4 0
3 years ago
A student determined that the area of the segment of c shown above is Asegment = 137.71 ft2. The student's work is shown below.
ivolga24 [154]

Answer:

Option D. The student did not use the correct formula to calculate the area of the segment

Step-by-step explanation:

step 1

Find the area of the isosceles triangle

Applying the law of sines

A=\frac{1}{2}(12^{2})sin(60\°)=62.35\ ft^{2}

step 2

Find the area of the sector

The area of the sector is 1/6 of the area of the circle

so

A=\pi r^{2}/6

substitute the value

A=(3.14)(12)^{2}/6=75.36\ ft^{2}

step 3

Find the area of the segment

The area of the segment is equal to the area of sector minus the area of triangle

A=75.36\ ft^{2}-62.35\ ft^{2}=13.01\ ft^{2}

therefore

The student did not use the correct formula to calculate the area of the segment

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3 years ago
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