Answer:
The probability there will be between 280 and 360 column inches of classified advertisement
P(280≤X≤360) = P(-2≤Z≤2) = 0.9544
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean the population = 320
The standard deviation of the Population = 20
Let 'X' be the random variable in a normal distribution
Let 'X' = 280
Let 'X' = 360
<u><em>Step(iii):-</em></u>
The probability there will be between 280 and 360 column inches of classified advertisement
P(280≤X≤360) = P(-2≤Z≤2)
= P(z≤2) -P(z≤-2)
= P(z≤2)+P(z≤2)
= 2P(z≤2)
= 2×0.4772 ( from normal table)
= 0.9544
21 chaperones are needed for 420 students.
Step-by-step explanation:
No. of juniors = 148
No. of seniors = 272
Total = 148+272 = 420 students
3 chaperones = 60 students
1 chaperone = 
Ratio of chaperon to students = 1:20
Let,
x be the number of chaperons for 420 students.
Ration of chaperones to students = x:420
Using proportion
Ratio of chaperones to students :: Ratio of chaperons to students
Product of mean = Product of extreme
Dividing both sides by 20
21 chaperones are needed for 420 students.
Keywords: ratio, proportion
Learn more about ratios at:
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He switched the 5 and 6 into different places
The Horizontal component is 554.889N and the vertical component is
9.8235 Newton
<h3>Resolution of Forces</h3>
Given Data
- Angle of Applied force = 44°
- Fx = Horizontal component of the applied force
- Fy = the vertical component of the applied force
Resolving the vertical force
Fy = 555 sin44°
Fy = 555 *0.01770
Fy = 9.8235 Newton
Resolving the horizontal force
Fx = 555 cos 44°
Fx = 555 *0.9998
Fx = 554.889 Newton
Learn more about forces here:
brainly.com/question/25997968
