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Mashcka [7]
3 years ago
9

A student has a savings account with d dollars in it. The student plans to withdraw w dollars each month for n months

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0

The equation for the balance in the student's account is b = d - nw.

<h3>What is the equation that represents the balance in the account?</h3>

The account balance reduces by the amount withdrawn every month. So, the account balance becomes smaller each month.

The equation that represents this situation is: beginning balance - (number of months x amount withdrawn)

d - (n x w)

b = d - nw

To learn more about mathematical equations, please check: brainly.com/question/26427570

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Find the distance between the two points. (-1, 6), (2, 8) Round to the nearest hundredth
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d = \sqrt{13} or d = 3.61

Step-by-step explanation:

d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(2-(-1))^2+(8-6)^2}\\d= \sqrt{(3)^2+(2)^2}\\d= \sqrt{9+4}\\d= \sqrt{13}

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9. A rectangle has a length 2 ft less than three times its width. What is the area of the rectangle when its
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Answer:

Area = 8 square ft

Step-by-step explanation:

Area of a rectangle = Length × width

suppose length = x

width  = y

Here it is given that  x = 3 y - 2

             width is given as y = 2 ft

            ∴ x = 3 × 2 -2

              x = 6 -2

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4 0
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Write the standard form of the equation for the circle that passes through the points (2,31),(-15,14),(33,0)
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Answer:

Step-by-step explanation:

Begin with the standard form of a circle as a conic:

Ax^2+Bxy+Cy^2+Dx+Ey+F=0

For a circle, A and C will be the exact same, and B will equal 0.  If B is non-zero, the equation represents a rotation of a conic, which is reserved for college-level courses.  Shortening this, then:

x^2+y^2+Dx+Ey+F=0 is good enough for us for this.  Start with the first point on the circle, (2, 31) and fill in the equation above with x and y:

2^2+31^2+2D+31E+F=0 which simplifies down to:

(1):2D+31E+F=-965

Do the same with the next point on the circle, (-15, 14):

-15^2+14^2-15D+14E+F=0 which simplifies down to:

(2):-15D+14E+F=0

Do the same with the last point, (33, 0):

33^2+0^2+33D+0E+F=0 which simplifies down to:

(3):33D+F=-1089

Now we will add (1) and (2) to get (4):

 2D + 31E + F = -965

-15D + 14E + F = -421

Multiply the top equatio by -1 to get rid of the F terms:

 -2D - 31E - F = 965

-15D + 14E + F = -421

which simplifies to

(4): -17D - 17E = 544

Now add (2) and (3) to get (5):

-15D + 14E + F = -421

33D           + F = -1089

Multiply the bottom equation by -1 to get rid of the F terms:

-15D + 14E + F = -421

-33D          - F = 1089

which simplifies to

(5): -48D + 14E = 668

Now add (4) and (5) together and eliminate the E terms:

-17D - 17E = 544

-48D + 14E = 668

In order to eliminate the E terms, multiply the top equation by 14 and the bottom equation by 17 to solve for D:

-238D - 238E = 7616

-816D + 238E = 11356

Which gives you that

D = -18

Now plug the value for D into (4) to find E:

-17(-18) - 17E = 544 and

306 - 17E = 544 and

-17E = 238 so

E = -14

Now plug the values for both D and E into (1) to find F:

2(-18) + 31(-14) + F = -965 and

-36 - 434 + F = -965 and

-470 + F = -965 so

F = -495

Now we can fill in the standard form of the conic:

x^2+y^2-18x-14y=495

but we're not done til we complete the square on both the x terms and the y terms (and I am assuming you know how to complete the square):

(x^2-18x+81)+(y^2-14y+49)=495+81+49 which simplifies to

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