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marissa [1.9K]
3 years ago
13

Hey guys! Leave the answer in terms of pi :)

Mathematics
1 answer:
DaniilM [7]3 years ago
8 0
A) if the diameter is 13 the radius is 6.5
(6.5 \times 6.5) \times \pi = 42.25\pi  \\  =  132.7323
b)if the diameter is 6 the radius will be 3
(3 \times 3) \times \pi = 9\pi  \\ = 28.27433
hope this helps
You might be interested in
Consider the function f(x) = 3x and the function g, which is shown below.
VLD [36.1K]

Answer:

<em>B. The graph of g is the graph of f shifted 2 units down</em>

Step-by-step explanation:

<u>Graph of Functions</u>

We have two functions:

f(x)=3^x

g(x)=3^x-2

Since g(x)=f(x)-2 it will be represented as an identical graph as that for f(x), but vertically displaced 2 units down. Let's check it by plugging some points

f(0)=3^0=1

g(0)=3^0-2=-1

f(1)=3^1=3

g(1)=3^1-2=1

f(3)=3^3=27

g(3)=3^3-2=25

We can notice the values of g(x) are always 2 units below f(x), thus the correct answer is

B. The graph of g is the graph of f shifted 2 units down

7 0
3 years ago
A bunch of 6 bananas costs $3.54. What is the unit rate?
mr_godi [17]
Divide 6 by 3.54
The quotient would be 1.69
Your answer is that the unit rate is $1.69 per banana
7 0
3 years ago
If g(x)=3x-1 and if g(a)=7 what is the value of a?
Ierofanga [76]

Answer:

a = 8/3

Step-by-step explanation:

3a - 1 would equal 7

3a = 7 + 1

3a = 8

a = 8/3

6 0
2 years ago
Please help! thanks so much​
Stels [109]

Answer:

See below.

Step-by-step explanation:

First, we can see that \lim_{x \to 2}  (f(x))= -1.

Thus, for the question, we can just plug -1 in:

\lim_{x \to 2} (\frac{x}{f(x)+1})=\frac{(2)}{-1+1}  =und.

Saying undefined (or unbounded) will be correct.

However, note that as x approaches 2, the values of y decrease in order to get to -1. In other words, f(x) will always be greater or equal to -1 (you can also see this from the graph). This means that as x approaches 2, f(x) will approach -.99 then -.999 then -.9999 until it reaches -1 and then go back up. What is important is that because of this, we can determine that:

\lim_{x \to 2} (\frac{x}{f(x)+1})=\frac{(2)}{-1+1}  = +\infty

This is because for the denominator, the +1 will always be greater than the f(x). This makes this increase towards positive infinity. Note that limits want the values of the function as it approaches it, not at it.

4 0
2 years ago
Simplify the expression(a4−6a2b2+ b4)−(−2a4+5a2b2+ 3b4) and hence, find its value for a = 2and b = −1.
ELEN [110]

Answer:

(a) 3a^4 - 11a^2b^2 -2b^4

(b) 3a^4 - 11a^2b^2 -2b^4= 2

Step-by-step explanation:

Given

(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Solving (a): Simplify

(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Open brackets

a^4 - 6a^2b^2+ b^4 +2a^4-5a^2b^2- 3b^4

Collect Like Terms

a^4 +2a^4- 6a^2b^2-5a^2b^2+ b^4 - 3b^4

Simplify Like Terms

3a^4 - 11a^2b^2 -2b^4

Solving (b): Simplify when a = 2 and b = -1

3a^4 - 11a^2b^2 -2b^4

3*(2)^4 - 11*(2^2)*(-1)^2 -2*(-1)^4

3 * 16 - 11 * 4 * 1 - 2 * 1

48 - 44 - 2

= 2

Hence:

3a^4 - 11a^2b^2 -2b^4= 2

4 0
2 years ago
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