Answer:
Step-by-step explanation:
1 = quadratic
2 = quadratic
3 = linear
4. quadratic
hope it is correct :D
Since you are given the area, we can solve for radius with this equation:
![A_c = \pi r^2](https://tex.z-dn.net/?f=A_c%20%3D%20%5Cpi%20r%5E2)
![r = \sqrt{ \frac{A_c}{ \pi } } = \sqrt{ \frac{121 \pi }{ \pi } } = \sqrt{121} = 11](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B%20%5Cfrac%7BA_c%7D%7B%20%5Cpi%20%7D%20%7D%20%3D%20%5Csqrt%7B%20%5Cfrac%7B121%20%5Cpi%20%7D%7B%20%5Cpi%20%7D%20%7D%20%3D%20%5Csqrt%7B121%7D%20%3D%2011%20)
The radius is 11, so the diameter must be 2 times that, which is 22. With the correct units, the answer is
22 units²
Answer:
1/2
Step-by-step explanation:
1/2
Alejandro is correct because you do not need to add another number to 76.518, as Jiro did, but you need to round it to the nearest tenth.
Glad I could help, and good luck!
Answer:
The area of the figure is 1,000 square feet
Step-by-step explanation:
we know that
The area of the kite ABCD
is equal to
![A=\frac{1}{2}[AC*BD]](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5BAC%2ABD%5D)
where
AC and BD are the diagonals of the kite
we have
![BD=50\ ft\\AC=40\ ft](https://tex.z-dn.net/?f=BD%3D50%5C%20ft%5C%5CAC%3D40%5C%20ft)
substitute
![A=\frac{1}{2}[40*50]=1,000\ ft^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5B40%2A50%5D%3D1%2C000%5C%20ft%5E2)