The number is 200 .
10 is 5% of 200
Answer:
Step-by-step explanation:
∠ABC = ∠BCD { AB // CD; BC TRAVERSAL, alternate angles are equal}
∠ABC = 20
∠BCA = ∠BAC {angles opposite to equal sides are equal}
∠BCA = ∠BAC = x
x + x + 20 = 180
2x = 180 - 20
2x = 160
x = 160/2
x = 80
Answer:
<I= 15degrees
Step-by-step explanation:
Using the cosine rule formulae;
j² = i²+k²-2i cos <J
j² = 37²+57² - 2(37)(57)cos <141
j² = 1369+ 3249- 4218cos <141
j² = 4618- 4218cos <141
j² = 4618-(-3,278)
j²= 7,896
j = √7,896
j = 88.86inches
Next is to get <I
i² = j²+k²-2jk cos <I
37² = 88.86²+57² - 2(88.86)(57)cos <I
1369 = 7,896.0996+ 3249- 10,130.04cos <I
1369 = 11,145.0996 - 10,130.04cos <I
1369 - 11,145.0996 = - 10,130.04cos <I
-9,776.0996=- 10,130.04cos <I
cos <I =9,776.0996 /10,130.04
cos<I = 0.96506
<I = 15.19
<I= 15degrees
Answer:
Go to the bottom of that problem and click save for later
(n-4)(n+11) so pretty much B
