Let's solve your equation step-by-step.
<span>0=<span>4+<span>n/5
</span></span></span>Step 1: Simplify both sides of the equation.<span>0=<span><span><span>1/5</span>n</span>+4
</span></span>Step 2: Flip the equation.<span><span><span><span>1/5</span>n</span>+4</span>=0
</span>Step 3: Subtract 4 from both sides.<span><span><span><span><span>1/5</span>n</span>+4</span>−4</span>=<span>0−4
</span></span><span><span><span>1/5</span>n</span>=<span>−4
</span></span>Step 4: Divide both sides by 1/5.<span><span><span><span>1/5</span>n/</span><span>1/5 </span></span>=<span><span>−4/</span><span>15</span></span></span><span>n=<span>−20
</span></span>Answer:<span>n=<span>−<span>20</span></span></span>
Answer:
Exfoliation
Step-by-step explanation:
Changes in temperature cause rock to expand (with heat) and contract (with cold). As this happens over and over again, the structure of the rock weakens. Over time, it crumbles.
Rocky desert landscapes are particularly vulnerable to thermal stress. The outer layer of desert rocks undergo repeated stress as the temperature changes from day to night. Eventually, outer layers flake off in thin sheets, a process called exfoliation.
Answer:
Probability distribution for x:

Step-by-step explanation:
We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.
The probability of k defective sets in the group is:

So, we have this probabilty distribution for x:
