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3 years ago

Which of the following does not belong with the other three? Explain your reasoning

Mathematics

1 answer:

Savatey [412]3 years ago

6 0

???????????I don't know exactly what you mean

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Find all natural numbers n such that 1+3+5+7+...+(2n-1) sum is divisible by 4

Ierofanga [76]

n ∈ natural even numbers

Step-by-step explanation:

1 + 3 + 5 + 7 + … + (2n-1)

a = 1
b = 2
Uₙ = 2n - 1

sum of the first n terms :

Sₙ = n/2(a + Uₙ)

Sₙ = n/2(1 + 2n - 1)

Sₙ = n/2(2n)

Sₙ = n²

∴ so, the solution of n is all natural even numbers

6 0

3 years ago

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Solve the equation. –4y + 8 = 4(2y – 2) + 4(8 - 2y)

ss7ja [257]

-Y+2=(2y-2)+(8-2y) @
Y=-4

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3 years ago

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9( 2k + 3 ) + 2 = 11 ( k- y )

Mashcka [7]

9(2k+3)+2=11 (k-y)
k=-11/7 y+ -29/7

8 0

3 years ago

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Please help me with finding the area

arsen [322]

Answer:

the Answer is 382.5

Step-by-step explanation:

Hope this Helps! :)

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3 years ago

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What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

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3 years ago