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Pavel [41]
3 years ago
7

Hộp đựng 3 bi đỏ, 5 bi trắng và 7 bi xanh lấy ngẫu nhiên 2 bi. Tính xác suất? a, Có 1 bi đỏ trong 2 bi lấy ra b, Có ít nhất 1 bi

đỏ trong 2 bi lấy ra
Mathematics
1 answer:
Vikentia [17]3 years ago
5 0

Answer:

a) 3C1 * 12 C1 / 15 C2

b)  1 - 12C2 / 15C2

Step-by-step explanation:

Được

Viên bi đỏ = 3

Viên bi trắng = 5

Viên bi xanh = 7

Hai quả bóng được rút ra một cách ngẫu nhiên

a) Có 1 bi đỏ

3C1 * 12 C1 / 15 C2

b) Có ít nhất 1 viên bi đỏ trong số 2 viên lấy ra.

Số kết quả của việc chọn hai quả bóng trong số 15 quả bóng = 15 C2

Số kết quả của việc chọn 0 quả bóng đỏ = 15C12

Xác suất chọn được ít nhất 1 viên bi đỏ = 1 - 12C2 / 15C2

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