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Black_prince [1.1K]
3 years ago
7

Last year, there were 20 students in a class. This year, there are 30% more students. How many students are in the class this ye

ar?
Mathematics
1 answer:
OleMash [197]3 years ago
6 0

Answer: Is 26 so

Gib brainliest pwease

Step-by-step explanation: Your dummy

before your account goes bye bye

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Using the following image, if you EG = 59, what are x, EF, and FG.
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Answer:

x=6\,\,units\,,\,EF=34 \,\,units\,,\,FG=25\,\,units

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Given: EG =59 \,\,units

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#11 i
Paraphin [41]

The area of a shape is the amount of space a shape can occupy, while the perimeter is the sum of its lengths.

  • <em>The perimeter is </em>18 + 3\sqrt 5 + 3\sqrt 2<em>units</em>
  • <em>The area of the sanctuary is 27 square units</em>

We have:

A = (5,7)\\B=(8, 7)\\C=(8, 1)\\D=( 1, 1)\\E=( 1, 4)\\F= ( 5,4)

<u>Perimeter</u>

See attachment for the layout of the sanctuary

BC = \sqrt{(8 - 8)^2 + (7 - 1)^2} = 6

EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4

FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3

From the attachment, the sides are

<em>AB, BF, FC, CD, DE and EA</em>

Start by calculating the length of each side using the following distance formula:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_2)^2}

So, we have:

AB = \sqrt{(5 - 8)^2 + (7 - 7)^2} = 3

BF = \sqrt{(8 - 5)^2 + (7 -1)^2} = \sqrt{45} = 3\sqrt 5

FC = \sqrt{(8 - 5)^2 + (1 -4)^2} = \sqrt{18} = 3\sqrt 2

CD = \sqrt{(8 - 1)^2 + (1 - 1)^2} = 7

DE = \sqrt{(1 - 1)^2 + (1 - 4)^2} = 3

EA = \sqrt{(1 - 5)^2 + (4 -7)^2} = 5

So, the perimeter (P) is:

P = AB + BF + FC + CD + DE + EA

P = 3 + 3\sqrt 5 + 3\sqrt 2 + 7 + 3 + 5

P = 18 + 3\sqrt 5 + 3\sqrt 2

<em>Hence, the perimeter is </em>18 + 3\sqrt 5 + 3\sqrt 2<em>units</em>

<u />

<u>Area</u>

To calculate the area, we need to divide the sanctuary into three.

  1. <em>Triangle ABF</em>
  2. <em>Triangle EFA</em>
  3. <em>Trapezium CDEF</em>

The area of ABF is:

Area = \frac 12 \times AB \times FA

Where:

AB = 3

FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3

Area = \frac 12 \times 3 \times 3

Area = \frac 92

The area of EFA is:

Area = \frac 12 \times EF \times FA

Where:

FA = 3

EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4

So:

Area = \frac 12 \times 4 \times 3

Area = 6

The area of CDEF is:

Area = \frac 12(CD + EF) \times DE

Where

CD = 7

EF = 4

DE = 3

So, we have:

Area = \frac 12 (7 + 4) \times 3

Area = \frac 12 \times 11 \times 3

Area = \frac {33}2

So, the area of the sanctuary is:

Area = \frac 92 + 6 + \frac {33}2

Area = \frac {9 +12 + 33}2

Area = \frac {54}2

Area = 27

<em>Hence, the area of the sanctuary is 27 square units</em>

Read more about areas and perimeters at:

brainly.com/question/11957651

8 0
3 years ago
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