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anyanavicka [17]
2 years ago
8

11 mm 5 mm The figure is the net for a rectangular prism. 4 mm 4 mm What is the surface area of the rectangular prism represente

d by the net? 5 mm 4 mm 11 mm Enter your answer in the box. mm 1 2.​
Mathematics
1 answer:
Butoxors [25]2 years ago
3 0

Answer:

348m

Step-by-step explanation:

I took the k12 test

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What's the difference between the largest number and the smallest 75,600, 7506 75,650 7,056 75,026
11111nata11111 [884]
<u>Largest:</u> 75,650
<u>Smallest:</u> 7,056
Subtract. 75,650-7,056= 68,594
Give 5 stars and brainliest answer if this helped please!
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Find the area of the figure.. Single choice.
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This is 130m squared
7 0
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in which place is the digit in the numbers 5,341 that would be changed to form 5,841? how do the values of the two numbers compa
Akimi4 [234]

The changed digit is the third to the left of the decimal point, so is in the hundreds place.

The value of 8 hundred is 5 hundred more than the value of 3 hundred. The second number is 500 more than the first.

7 0
3 years ago
0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?
MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So,  4# · 3# · 2# · 1#? =  6912 · 24 · 2 · 1? = 331776

7 0
3 years ago
Plsss Help me plsssssssssssss
Mazyrski [523]

Answer:

If, a = 2 and b = 3

<h3>Jada</h3><h3>10a + 1b = 7a + 5b  - 3a + 4b \\ 10(2) + 1(3) = 7(2) + 5(3) - 3(2) + 4(3) \\ 20 + 3 = 14 + 15 - 6 + 12 \\ 23 = 35 \\</h3>

It's not equivalent.

<h3>Diego</h3><h3>4a + 9b = 7a + 5b - 3a + 4b \\ 4(2) + 9(3) = 7(2) + 5(3) - 3(2) + 4(3) \\ 8 + 27 = 14 + 15 - 6 + 12 \\ 35 = 35 \\</h3>

It's equivalent.

The correct equation is 4a + 9b.

5 0
2 years ago
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