3 years ago

What is the value of x? Please help ASAP 20 Pts.

Mathematics

1 answer:

Sindrei [870]3 years ago

5 0

Where is the attachment?

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Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?

oee [108]

The answer is $\frac{x^{4/3}y^{3}}{3}$ .

The fraction is: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }$
Let's rewrite it: $\frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }$

Since $\frac{x^{a} }{x^{b}} =x^{a-b}$ ,
then:
*** $\frac{x}{ x^{-1/3} }= x^{1-(-1/3)} = x^{3/3+1/3} = x^{4/3}$
*** $\frac{y^{-2} }{ y^{-5} }= y^{-2-(-5)} = y^{-2+5} = y^{3}$
______
$\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}$

8 0

3 years ago

!!!!Which ordered pair in the form of (x, y) are solutions to the equation 7x - 5y =28

muminat

Answer:

(-6,-14)

Step-by-step explanation:

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3 years ago

For what values of x is the expression below defined?<br> √x+4÷√1-x

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