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Alex73 [517]
2 years ago
4

Evaluate e0.2 to four decimal places

Mathematics
1 answer:
____ [38]2 years ago
7 0

Answer:

grab

Step-by-step explanation:

hahahahaha

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Please help me with :)))​
Doss [256]
I think your answer is 90
5 0
3 years ago
How do you use a number line to find 3/4 times 2/5
Verizon [17]

Answer:

First, you need to find the number 2/5 on the number line.

Now, you want to find (3/4) times (2/5)

Then the distance between 0 and the point you found earlier needs to be divided into four equal parts (because the denominator is 4)

sAnd because we have the factor (3/4), with a numerator equal to 3, we move from the origin 3 of these parts to the right, the point at where you arrived is the point (3/4)*(2/5)

Another way, which should give you the exact same point, is:

First locate the point (3/4) on the number line.

Now, you want to find (3/4) times (2/5)

The distance between zero and the denominator needs to be divided into 5 parts (because the denominator is 5)

Because the numerator is 2, you need to move, from the origin, two of these parts to the right.

The point where you end is the product (3/4)*(2/5)

4 0
3 years ago
Write the equation in slope-intercept. y - 7 = -3⁄4 (x +5)
denpristay [2]

Answer:

Step-by-step explanation: . y - 7 = -3⁄4 (x +5)

1. y = -3/4(x+5) + 7

2. y = -3/4x + -15/4 + 7

3. y = -3/4x + 13/4

4 0
3 years ago
Find (f×g)(x) when f(x)=x^2+8x+15 and g(x)=5 over x^2-9
Kipish [7]
Look at the picture......

5 0
3 years ago
I really need help I’ve worked it out already though
Vikki [24]
<h2><em>Answer</em><em>:</em></h2><h3><em>7</em><em>5</em><em>(</em><em>5</em><em>r</em><em>)</em><em>+</em><em>7</em><em>5</em><em>(</em><em>3</em><em>d</em><em>)</em><em>+</em><em>7</em><em>5</em><em>(</em><em>4</em><em>f</em><em>)</em></h3>

<em>Solution</em><em>,</em>

<em>Cost </em><em>of </em><em>roses </em><em>in </em><em>1</em><em> </em><em>bouquet=</em><em>5</em><em>r</em>

<em>Cost </em><em>of </em><em>daisies </em><em>in </em><em>1</em><em> </em><em>bouquet=</em><em>3</em><em>d</em>

<em>cost </em><em>of </em><em>green </em><em>filler </em><em>in </em><em>1</em><em> </em><em>bouquet</em><em>=</em><em>4</em><em>f</em>

<em>Total </em><em>no.</em><em> </em><em>of </em><em>bo</em><em>u</em><em>q</em><em>u</em><em>e</em><em>t=</em><em>7</em><em>5</em>

<em>cost </em><em>of </em><em>one </em><em>bouquet=</em><em>5</em><em>r</em><em>+</em><em>3</em><em>d</em><em>+</em><em>4</em><em>f</em>

<em>total=</em><em>7</em><em>5</em><em>(</em><em>5</em><em>r</em><em>+</em><em>3</em><em>d</em><em>+</em><em>4</em><em>f</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>7</em><em>5</em><em>(</em><em>5</em><em>r</em><em>)</em><em>+</em><em>7</em><em>5</em><em>(</em><em>3</em><em>d</em><em>)</em><em>+</em><em>7</em><em>5</em><em>(</em><em>4</em><em>f</em><em>)</em>

<em>hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

8 0
3 years ago
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