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3 years ago

Help please I’m begging you

Mathematics

2 answers:

zzz [600]3 years ago

8 0

Answer:

Step-by-step explanation:

add to eliminate y

irga5000 [103]3 years ago

6 0

Answer:

subtract to eliminate y

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I dont know this one too??

Maslowich

Answer:

bottom left

Step-by-step explanation:

line of symmetry means that both sides will look the same if a line is drawn thru

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2 years ago

A pipe is leaking at the rate of 32 fluid ounces per minute. Use dimensional analysis to find out how many gallons the pipe is l

lianna [129]

well first think about it, 60 min in an hour, so 32 fluid ounces times 60 = 1920 fluid ounces, from there you can convert fluid ounces to practically anything, for instance, 1920 fluid ounces = 24 cups.

go to this address to find out more.

https://www.google.com/search?q=another+name+for+observations&rls=com.microsoft:en-US:IE-Address&ie=...

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3 years ago

Read 2 more answers

What is the solution to the inequality -4 x < 8?

alekssr [168]

Answer:

The solution of the inequality is x < -2.

Step-by-step explanation:

Let's simplify the inequality first.

=> -4x < 8
=> -4x/4 < 8/4
=> -x < 2
=> x < -2

Hence, the solution of the inequality is x < -2.

Hoped this helped.

$BrainiacUser1357$

6 0

2 years ago

Read 2 more answers

Write a kinda short song about 1 polygon with a familiar tune

STALIN [3.7K]

A triangle is A polygon with 3 angles(x2) 3 sides

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3 years ago

An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the

julia-pushkina [17]

Answer:

The rate of decrease is: $43.2mm^3/min$

Step-by-step explanation:

Given

$l = 18mm$

$\frac{dl}{dt} = -0.8mm/min$ ---- We used minus because the rate is decreasing

Required

Rate of decrease when: $l = 18mm$

The volume of the cube is:

$V = l^3$

Differentiate

$\frac{dV}{dl} = 3l^2$

Make dV the subject

$dV = 3l^2 \cdot dl$

Divide both sides by dt

$\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}$

Given that: $l = 18mm$ and $\frac{dl}{dt} = -0.8mm/min$

$\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)$

$\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min$

$\frac{dV}{dt} = -43.2mm^3/min$

Hence, the rate of decrease is: 43.2mm^3/min

8 0

3 years ago