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2 years ago

Find the domain and range pls!

Mathematics

1 answer:

skad [1K]2 years ago

4 0

Domain should be, (-♾️,♾️)
And range should be, (-♾️, 2)

If you ment something other then this please message me so I can help!

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Linear graphing y= -2x

Vlad1618 [11]

Let x = 0. What do you get for y?
This gives you one point.

Then let x = 1. What do you get for y.
This gives you a second point.

3 0

3 years ago

Check whether 7+3x is a factor of 3x^3+7x

BartSMP [9]

Answer:

Step-by-step explanation:

refer to picture for solution

3 0

3 years ago

In 2003, the annual sales at a company are $372,000. If sales are increasing at a rate

Otrada [13]

Answer:

20 years

Step-by-step explanation:

We start by writing an exponential equation;

FV = PV( 1 + r)^t

FV is the future value = 1,000,000

PV is present value = 372,000

r is rate = 5% = 5/100 = 0.05

t is time which we are looking for

1,000,000 = 372,000(1 + 0.05)^t

1.05^t = 1,000,000/372,000

1.05^t = 2.688

t ln 1.05 = ln 2.688

t = ln 2.688/ln 1.05

t = 20 years

3 0

3 years ago

Please help thank you very much

-BARSIC- [3]

Hello!

The answer is 34°

Hope this helps!

7 0

3 years ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago