In the unit circle the hypotenuse of the triangle formed is equal to radius of circle , which = 1. The point on the circle formed by the intersection of the hypotenuse is (cos q , sin q) where q is the angle between the x axis and the hypotenuse. As the hypotenuse = 1 the opposite and adjacent sides of the triangle < 1 so sin and cos of q must both be <= 1.
The value of a=9,b=3 and c=1
Step-by-step explanation:
The graph shown is for function f(x)
The given function is f(x)=
Table says,
X Y
-2 a
1 b
0 c
1 (1/3)
2 (1/9)
To find value of a:
From table, for output value a, input value, x=(-2)
we can write f(-2)=a
Therefore,
f(x)=
f(-2)=
a=
a=
a=9
To find value of b:
From table, for output value a, input value, x=(-1)
we can write f(-1)=b
Therefore,
f(x)=
f(-1)=
b=
b=
b=3
To find value of c:
From table, for output value a, input value, x=(0)
we can write f(0)=c
Therefore,
f(x)=
f(0)=
c=
c=1
It was multiply (z - 12) by 2 because you have to multiply everything in the parentheses