The atomic mass of beryllium (Be) is 9 g/mole
Now, 1 mole of any substance contains avogadro's number of that substance. Therefore:
1 mole of Be contains 6.023 10^23 atoms of Be
In other words:
9 grams of Be contains 6.023*10^23 atoms of Be
Therefore, the mass corresponding to 9.76 * 10^12 atoms of Be is:
= 9 g * 9.76 10^12 atoms/6.023*10^23 atoms
= 1.458 * 10^-10 g (or) 1.46 * 10^-10 g
Answer:
Explanation:
To make a distinction in favor of or against a person or thing on basic or group, class or category, to which the person or thing(s) belong
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